TaxControlAppTest/third-party/folly-2018.10.22.00/folly/experimental/pushmi/examples/composition/composition_2.cpp

/*
 * Copyright 2018-present Facebook, Inc.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *   http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */
#include <algorithm>
#include <cassert>
#include <iostream>
#include <vector>

#include <folly/experimental/pushmi/examples/pool.h>

#include <folly/experimental/pushmi/o/transform.h>
#include <folly/experimental/pushmi/o/via.h>
#include <folly/experimental/pushmi/strand.h>

using namespace pushmi::aliases;

struct f_t {};
f_t f() {
  return {};
}
struct g_t {};
g_t g(f_t) {
  return {};
}

// these expressions are read backward, bottom-right to top-left
template <class CPUExecutor, class IOExecutor>
void lisp(CPUExecutor cpu, IOExecutor io) {
  // f on cpu - g on cpu (implicit: a single task on the cpu executor runs all
  // the functions)
  op::submit([](g_t) {})(op::transform([](f_t ft) { return g(ft); })(
      op::transform([](auto) { return f(); })(cpu)));

  // f on cpu - g on cpu (explicit: the first cpu task runs f and a second cpu
  // task runs g)
  op::submit([](g_t) {})(op::transform([](f_t ft) { return g(ft); })(
      op::via(mi::strands(cpu))(op::transform([](auto) { return f(); })(cpu))));

  // f on io  - g on cpu
  op::submit([](g_t) {})(op::transform([](f_t ft) { return g(ft); })(
      op::via(mi::strands(cpu))(op::transform([](auto) { return f(); })(io))));
}

template <class CPUExecutor, class IOExecutor>
void sugar(CPUExecutor cpu, IOExecutor io) {
  // f on cpu - g on cpu (implicit: a single task on the cpu executor runs all
  // the functions)
  cpu | op::transform([](auto) { return f(); }) |
      op::transform([](f_t ft) { return g(ft); }) | op::submit([](g_t) {});

  // f on cpu - g on cpu (explicit: the first cpu task runs f and a second cpu
  // task runs g)
  cpu | op::transform([](auto) { return f(); }) | op::via(mi::strands(cpu)) |
      op::transform([](f_t ft) { return g(ft); }) | op::submit([](g_t) {});

  // f on io  - g on cpu
  io | op::transform([](auto) { return f(); }) | op::via(mi::strands(cpu)) |
      op::transform([](f_t ft) { return g(ft); }) | op::submit([](g_t) {});
}

template <class CPUExecutor, class IOExecutor>
void pipe(CPUExecutor cpu, IOExecutor io) {
  // f on cpu - g on cpu (implicit: a single task on the cpu executor runs all
  // the functions)
  mi::pipe(
      cpu,
      op::transform([](auto) { return f(); }),
      op::transform([](f_t ft) { return g(ft); }),
      op::submit([](g_t) {}));

  // f on cpu - g on cpu (explicit: the first cpu task runs f and a second cpu
  // task runs g)
  mi::pipe(
      cpu,
      op::transform([](auto) { return f(); }),
      op::via(mi::strands(cpu)),
      op::transform([](f_t ft) { return g(ft); }),
      op::submit([](g_t) {}));

  // f on io  - g on cpu
  mi::pipe(
      io,
      op::transform([](auto) { return f(); }),
      op::via(mi::strands(cpu)),
      op::transform([](f_t ft) { return g(ft); }),
      op::submit([](g_t) {}));
}

int main() {
  mi::pool cpuPool{std::max(1u, std::thread::hardware_concurrency())};
  mi::pool ioPool{std::max(1u, std::thread::hardware_concurrency())};

  lisp(cpuPool.executor(), ioPool.executor());
  sugar(cpuPool.executor(), ioPool.executor());
  pipe(cpuPool.executor(), ioPool.executor());

  ioPool.wait();
  cpuPool.wait();

  std::cout << "OK" << std::endl;
}